» » Sort object using comparable interface

  1. package com.instanceofjava;
  2.  
  3. import java.util.Comparable;
  4.  
  5. public class Employee implements Comparable<Employee> {
  6.  
  7.  int id;
  8.  String name;
  9.  
  10.  public Employee(int id, String name) {
  11. this.id=id; 
  12. this.name=name;
  13.  }
  14.  
  15.  public int getId() {
  16. return id;
  17.  }
  18.  
  19.  public void setId(int id) {
  20.   this.id = id;
  21.  }
  22.  
  23.  public String getName() {
  24. return name;
  25.  }
  26.  
  27.  public void setName(String name) {
  28.   this.name = name;
  29.  }
  30.  
  31.  @Override
  32.  public int compareTo(Employee e) {
  33.  
  34.  Integer i= this.getId();
  35.  Integer j=e.getId();
  36.  
  37.      if (this.getId() == e.getId())
  38.        return 0;
  39.       if (this.getId() < e.getId())
  40.         return 1;
  41.       if (this.getId() > e.getId())
  42.        return -1;
  43.       return 0;
  44. }
  45. }

  1. package com.oops;
  2. import java.util.ArrayList;
  3. import java.util.Collections;
  4. import java.util.Iterator;
  5. import java.io.*;
  6.   class Main{  
  7.  
  8. public static void main(String args[]){
  9.  
  10.  ArrayList al=new ArrayList();  
  11.  
  12.  al.add(new Employee(101,"Indhu"));
  13. al.add(new Employee(106,"Sindhu"));
  14.  al.add(new Employee(105,"Swathi"));  
  15. Collections.sort(al);
  16.  
  17. Iterator itr=al.iterator();   
  18.  
  19. while(itr.hasNext()){
  20.  
  21.    Employee st=(Employee)itr.next();
  22.    System.out.println(st.id +" "+st.name );   
  23.  
  24.   } 
  25. }  
  26.  
  27. }  
Output:
  1. Indhu 
  2. Swathi 
  3. Sindhu

 

Instance Of Java

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