We can not override private methods in java.
The basic inheritance principle is when we are extending a class we can access all non private members of a class so private members are private to that class only we can not access anywhere outside the class if we declare anything as private.
Know more information about access specifiers here

Class A{
int a;
private int b;
public void print(){
System.out.println("print method of super class A");
}
private void add(){
System.out.println("add method of super class A");
}
}
Class B extends A{
public void show(){
System.out.println("show method of sub class B");
}
public static void main(String[] args){
B obj= new B();
obj.a=30;
obj.print();
obj.show();
System.out.println("a="obj.a);
//obj.b=20; compile time error. The field Super.a is not visible
//obj.add(); compile time error : The method show() from the type Super is not visible
}
}

Output:

From the above program we can say super class private members are not accessible to sub class.
lets see what will happen if we try to override a method of super class?
Sorry if we are unable to access super class private methods then there should not be a questions of overriding that method right?
Yes private methods of super class can not be overridden in sub class.
Even if we try to override same method of super class that will became a sub class own method not overridden method.

Output:

Class A{
int a;
private int b;
private void add(){
System.out.println("add method of super class A");
}
}
Class B extends A{
//@override
private void add(){// if we place @override annotation compile time error will come here
System.out.println("add method of sub class B");
}
public static void main(String[] args){
B obj= new B();
obj.a=30;
obj.add();
System.out.println("a="obj.a);
}
}

Output:

Can we override private method in java

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