» » Java Program to find Sum of Digits


1. Java Program to find sum of digits without using recursion.

  1. package com.instaceofjava;
  2. import java.util.Scanner;
  3.  
  4. public class SumOfDigits {
  5.  
  6. public static void main(String[] args) {
  7.  
  8. int number;
  9. Scanner in = new Scanner(System.in);
  10.  
  11. System.out.println("Please Enter a number");
  12.  
  13. number=in.nextInt(); 
  14.  
  15. int sum=0 ;
  16.  
  17. while(number!=0){
  18.  
  19. sum=sum+(number%10);
  20. number=number/10;
  21. }
  22.  
  23. System.out.println("Sum of Digits ="+sum);
  24.  
  25. }
  26. }
Output:

  1. Please Enter a number
  2. 123
  3. Sum of Digits=6


2. Java Program to find sum of digits using recursion.

  1. package com.instaceofjava;
  2. import java.util.Scanner;
  3.  
  4. public class SumOfDigits {
  5.  
  6. int sum;

  7. public int CalRecSum(int n){
  8.  
  9. if(n==0){
  10. return sum;
  11. }
  12. else{
  13.  
  14.  sum+=n%10;
  15.  CalRecSum(n/10);
  16.  
  17.  
  18. return sum;
  19. }

  20. public static void main(String[] args) {
  21.  
  22. int number;
  23. Scanner in = new Scanner(System.in);
  24.  
  25. System.out.println("Please Enter a number");
  26.  
  27. number=in.nextInt(); 
  28.  
  29. SumOfDigits   ob= new SumOfDigits();
  30. System.out.println("Sum of Digits ="+ob.CalRecSum(number));
  31.  
  32. }
  33.  
  34. }


Output:

  1. Please Enter a number
  2. 326
  3. Sum of Digits=11

Instance Of Java

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3 comments for Java Program to find Sum of Digits

  1. public class SumOfDigits {
    public static void main(String[] args) {
    String a = String.valueOf(123456);
    String aa[] = a.split("");
    int sum =0;
    for(String bb:aa){
    if(!bb.equals(""))
    sum=sum+(Integer.valueOf(bb));
    }
    System.out.println(sum);


    }
    }

    ReplyDelete
  2. public static sumDigits(int number){
    return sumDigits(number, 0);
    }

    private static sumDigits(int number, int sum) {
    return number == 0 ? sum : sumDigits(number / 10, sum + number % 10);
    }

    ReplyDelete
  3. I faced this question in AGILE CRM company interview. Thanks :)

    ReplyDelete

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