Find top two maximum numbers in a array java

• Hi Friends today we will discuss about how to find top two maximum numbers in an array using java program.
• For this we have written separate function to perform logic
• findTwoMaxNumbers method takes integer  array as an argument
• Initially take two variables to find top to numbers and assign to zero.
• By using for each loop iterating array and compare current value with these values
• If our value is less than current array value then assign current value to max1 
• And assign maxone to maxtwo because maxtwo should be second highest.
• After completion of all iterations maxone will have top value and maxtwo will have second maximum value.
• Print first maximum and second maximum values.
• So from main method create array and pass to findTwoMaxNumbers(int [] ar).

Program #1: Java interview programs to practice: find top two maximum numbers in an array without recursion 

1. package arraysInterviewPrograms.instanceofjava;
2. public class FindTopTwo {
3.  
4. public void findTwoMaxNumbers(int[] array){
5.        
6.  int maxOne = 0;
7.  int maxTwo = 0;
8.  
9. for(int i:array){
10.  
11.     if(maxOne < i){
12.            maxTwo = maxOne;
13.            maxOne =i;
14.      } else if(maxTwo < i){
15.                 maxTwo = i;
16.      }
17. }
18.         
19.  
20.   System.out.println("First Maximum Number: "+maxOne);
21.   System.out.println("Second Maximum Number: "+maxTwo);
22. }
23.      
24. public static void main(String a[]){
25.  
26.         int num[] = {4,23,67,1,76,1,98,13};
27.         FindTopTwo obj = new FindTopTwo();
28.         obj.findTwoMaxNumbers(num);
29.         obj.findTwoMaxNumbers(new int[]{4,5,6,90,1});
30.  
31. }
32.  
33. }

Output:

1. First Maximum Number: 98
2. Second Maximum Number: 76
3. First Maximum Number: 90
4. Second Maximum Number: 6

Program #2:Java program to find top two maximum numbers in an array using eclipse IDE